Question

The product of the zeros of polynomial
$k {x}^{3} - 6x ^{2} + 11x - 6$
is 4 then K =???

Answer 1

Hey!!

p ( x ) = kx^3 - 6x^2 + 11x - 6

Product of zeroes = - d / a

=> 4 = - ( - 6 ) / k

=> 4 = 6 / k

=> 4k = 6

=> k = 6 / 4

=> k = 3 / 2 >>>>>> Answer


Hope it will helps you ✌