If a³+b³+c³=3abc ,then prove that a+b+c=0.
adarsharyan46:
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Answered by
2
Answer:
From the given equation a^3+b^3+c^3=3abc
Here by using the algebraic identity :
a^3+b^3+c^3-3abc=(a+b+c) (a^2+b^2+c^2-ab-bc-ac)
Substitute the values of the formula
(a+b+c)(a^2+b^2+c^2-ab-bc-ac)=0
(a+b+c)=0
Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
Firstly,
take to LHS
Now,
[ we know that = ]
hence,
⇒ = 0
Now we take to RHS so it multiplies with 0
giving us,
Hence proved..
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