if a3+b3+c3=3abc,then the value of a+b+c=?
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a³ + b³ + c³ - 3abc = ( a + b + c ) ( a² + b² + c² - ab - bc - ca )
when , ( a + b + c ) = 0
then , a³ + b ³ + c³ - 3abc = 0
a³+ b³ + c³ = 3abc
when , ( a + b + c ) = 0
then , a³ + b ³ + c³ - 3abc = 0
a³+ b³ + c³ = 3abc
Sgarai:
how can elaborate?
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