If a4 + b4 = a2 Show that a6 + b6 =
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Answer:
a⁶ + b⁶ = 0
Step-by-step explanation:
Correct Question
a⁴ + b⁴ = a²b²
=> (a²)² + (b²)² = a²b²
putting
x = a² y = b²
=> x² + y² = xy
=> x² + y² - xy = 0
a⁶ + b⁶
= (a²)³ + (b²)³
= x³ + y³
= (x + y)(x² + y² - xy)
= (x + y) * 0
= 0
a⁶ + b⁶ = 0
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