Question

If AA + BB = CC where A, B & C are different digits and none of them is Zero, find how many different solutions exist. E.g. (A,B,C) can be (1,4,5), (3,5,8), (4,1,5), and so on. (4,1,5) and (1,4,5) are different solutions because in (4,1,5), A=4 and in (1,4,5), A=1.​

Answer 1

AA=A*A=3*4=12

BB=B*B=5*1=5

CC=C*C=8*5=40

THE SUM OF AA+BB+CC=12+5+40=57

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