If aabb is a 4-digit perfect square no. then find the value of (a+b).Show ur working.
Answers
Answered by
23
number aabb can be written in the form
=1000a+100a+10b+b
=1100a+11b = 11(100a+b)
aabb=11*11*nsquare
whn n = 8
11*11*8=121*64=7744
this is in the form aabb
a+b=11
=1000a+100a+10b+b
=1100a+11b = 11(100a+b)
aabb=11*11*nsquare
whn n = 8
11*11*8=121*64=7744
this is in the form aabb
a+b=11
Answered by
19
Answer:11
Step-by-step explanation:
number aabb can be written in the form
=1000a+100a+10b+b
=1100a+11b = 11(100a+b)
We know that it is divisible by 11 so divide aabb by 11
You will get quotient as a0b.
Now as it is a square number aob will be also divisible by 11
So apply divisibility rule of 11
a+b -0=11
thus it is a better answer without guessing.
Similar questions
Hindi,
8 months ago
Math,
8 months ago
Computer Science,
8 months ago
Social Sciences,
1 year ago
Chemistry,
1 year ago
Science,
1 year ago
Math,
1 year ago