Question

If AB = 12 cm, BC = 16 cm and AB is perpendicular to BC, then the radius of the circle passing

through the points A, B and C is :​

Answer 1

Answer:

Given- A,B & C are points such that AB=12cm and BC=16cm and BC⊥AB.

To find out- the radius of the circle passing through A,B & C=?

Solution- BC⊥AB i.e ∠ABC=90

0

and ΔABC is a right one with AC as hypotenuse. ∴AC=

AB

2

+BC

2

=

12

2

+16

2

cm=20cm. So the circle passing through A,B & C will have its diameter as AC.

∴ Its radius=

2

1

×20cm=10cm.

Ans- Option C.

solution