Question

if AB =12 cm,BC =16cm and AB is perpendicular BC ,then what is the radius of the circle passing through the points A,B and C?​

Answer 1

Answer:

Hi bro, Think this helps :)

Step-by-step explanation:

Given : AB = 12 cm, BC = 16 cm and AB is ⊥ to BC

Hypotenuse² = Perpendicular² + Base²

⇒ AC² = AB² + BC²

⇒ AC² = 12² + 16²

⇒ AC² = 144 + 256

⇒ AC² = 400 

⇒ AC = √400

AC = 20 cm

Therefore,

r = hypotenuse/2

r = 20/2

Radius of the circle = 10 cm

Answer 2

ANSWER:

10cm

EXPLANATION:

Given:

AB = 12 cm,

BC = 16 cm

AB ⊥ BC

Method used : Pythagoras Theorem,

{ Hypotenuse² = Perpendicular² + Base²}

⇒ AC² = AB² + BC²

⇒ AC² = 12² + 16²

⇒ AC² = 144 + 256

⇒ AC² = 400  

⇒ AC = √400

AC = 20 cm

Hypotenuse = AC = 2r

r = AC/2

r = 20/2

∴Radius = 10 cm