Question

if AB = 13 cm , BD = 5 cm and DC = 16 cm,
find the values of :-
(1) sin B
(2) sec B
(3) cot B
(4) cos C
(5) cosec C
(6) tan C​

Answer 1

Answer:

Step-by-step explanation:AD^2=AB^2-BD^2=13^2-5^2=169-25=144

=>AD=12cm

(1)sin B=P/H=AD/AB=12/13

(2)sec B=H/B=AB/BD=13/5

(3)cot B=B/P=BD/AD=5/12

AC^2=AD^2+DC^2=12^2+16^2=144+256=400

=>AC=20cm

(4)cos C=B/H=CD/AC=16/20=4/5

(5)cosec C=H/P=AC/AD=20/12=5/3

(6)tan C =P/B=AD/DC=12/16=3/4

note:P=perpendicular

B=base

H=hypotenuse

Answer 2

Answer:

Hi mate Answer is in Pic. I have done In Notebook