Math, asked by supriya333333, 4 months ago

If ab=4 and a-b=8,then find a^2+b^2​

Answers

Answered by dharmdipt19
1

Step-by-step explanation:

ab=4 and a-b=8

then by formula

(a-b)^2=a^2+b^2-2ab

(8)^2=a^2+b^2-2×4 ( substituting the values of a^2+b^2 and ab)

64=a^2+b^2-8

64-8=a^2+b^2

a^2+b^2=56

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Answered by Anonymous
0

Answer:

a² + b² = (a-b)² + 2ab

= 8² + (2 × 4)

= 64 + 8

therefore,

a² + b² = 72

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