If ab=4 and a-b=8,then find a^2+b^2
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Answered by
1
Step-by-step explanation:
ab=4 and a-b=8
then by formula
(a-b)^2=a^2+b^2-2ab
(8)^2=a^2+b^2-2×4 ( substituting the values of a^2+b^2 and ab)
64=a^2+b^2-8
64-8=a^2+b^2
a^2+b^2=56
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Answered by
0
Answer:
a² + b² = (a-b)² + 2ab
= 8² + (2 × 4)
= 64 + 8
therefore,
a² + b² = 72
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