Question

If ab=ac=1 in a right angled triangle abc, find tanb+tanc

Answer 1

Given:

Triangle ABC is a right-angled triangle.

$AB = AC = 1$

To Find:

$\tan B + \tan C$

Solution

Find tan B:

$\tan \theta = \dfrac{\text{opposite}}{\text{adjacent}}$

$\tan B= \dfrac{\text{1}}{\text{1}}$

$\tan B= 1$

Find tan C:

$\tan \theta = \dfrac{\text{opposite}}{\text{adjacent}}$

$\tan C= \dfrac{\text{1}}{\text{1}}$

$\tan C= 1$

Find tan B + tan C:

$\tan B + \tan C = 1 + 1$

$\tan B + \tan C = 2$

Answer: 2