if AB=AC and angle ACD=105 degree, find angle BAC
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AB=AC then it is an isosceles triangle then it will be 75॰
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let's take X as angle BAC , 1 as angle ABC and 2 as angle ACB.
so angle 2 = 180° - 105° = 75°
so as the line AB = AC
so angle 1 = angle 2 = 75°
as we know that the sum of all interior angles is 180°
so angle 1 + angle2 + angle X = 180°
so X = 180 - (75 + 75)
X = 180 - 150
X= 30°
so angle 2 = 180° - 105° = 75°
so as the line AB = AC
so angle 1 = angle 2 = 75°
as we know that the sum of all interior angles is 180°
so angle 1 + angle2 + angle X = 180°
so X = 180 - (75 + 75)
X = 180 - 150
X= 30°
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