Collar AA is connected as shown to a 50 -lb load and can slide on a frictionless horizontal rod. Determine the distance x for which collar is in equilibrium when p=48 lb
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Answer:
2mg−T=(2m)a
T−mg=ma
⇒a=g/3
T=
3
4mg
w=T×s=T×
2
1
at
2
=
3
4mg
×
2
1
×
3
g
×1
2
=
9
200
×0.36=8Joules
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