If AB = AC and BD = CD, then prove that angle ABD = angle ACD.
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Answered by
6
Answer.
In ∆ABC
D is a point on side BC ,
Join A and D
GIVEN =>
AB=AC
BD=CD
PROVE=>
angle. ABD=angle ACD
SOLUTION=>
In ∆ ABD and ∆ ACD
AB = AC
BD= CD
AD =AD. ( common)
so ∆ ABC =_ { ~} ∆ ACD
so ∆ ABC cogurant to ∆ ACD. by (sss)
by cpct
angle ABD= angle ACD
In ∆ABC
D is a point on side BC ,
Join A and D
GIVEN =>
AB=AC
BD=CD
PROVE=>
angle. ABD=angle ACD
SOLUTION=>
In ∆ ABD and ∆ ACD
AB = AC
BD= CD
AD =AD. ( common)
so ∆ ABC =_ { ~} ∆ ACD
so ∆ ABC cogurant to ∆ ACD. by (sss)
by cpct
angle ABD= angle ACD
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Answered by
1
Answer:
the above or below ans is wrong the person has used triangle abd and acd because they are angle and it is by cpct sas congruence property .
Step-by-step explanation:
angle b = angle c
by sas
and the ratio is 1:1
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