Question

If AB and CD are the common

tangents in the circles of two unequal

(different) radii then show that

seg AB ≅ seg CD​

Answer 1

Step-by-step explanation:

the explanation is given above

Answer 2

Given :- If AB and CD are the common tangents in the circles of two unequal (different) radii then show that seg AB ≅ seg CD .

Solution :-

Let AB and CD intersect at point P when produced .

now, In circle with centre O, we have,

→ AP = CP ------------- Eqn.(1) { Tangents from same external points P to the circle are equal. }

similarly, In circle with centre O', we have,

→ BP = DP ------------- Eqn.(2) { Tangents from same external points P to the circle are equal. }

Subtracting Eqn.(2) from Eqn.(1), we get,

→ AP - BP = CP - DP

→ AB = CD .

therefore,

→ seg AB ≅ seg CD (Proved.)

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