Question

Two dice are thrown simultaneously. Find the probability of: 1. getting a multiple of 3 as the sum

Answer 1

Answer:p(multiple of 3 as sum)

P=12/36

Step-by-step explanation:

You can get a sun which is a multiple of 3 as follows: 1,2; 1,5; 2,1; 2,4; 3,3; 3,6; 4,2; 4,5; 5,1; 5;4, 6,3; 6,6. Hence 12/36. Possible Sum of two dice values = 2 3 4 5 6 7 8 9 10 11 12 over 36 total outcomes. Total 12 outcomes

Answer 2

Answer:

1/3

Step-by-step explanation:

Probability = no. of favorable outcomes / total no. of outcomes

When two dice are thrown, the total no. of outcomes are $6^{2}$ = 36

The maximum sum of numbers on the dice is 12 and minimum is 3.

Therefore, the multiples of 3 in between these numbers are 3, 6, 9, 12.

So, the favorable outcomes are, (1,2), (1,5), (2,1), (2,4), (3,3), (3,6), (4,2), (4,5), (5,1), (5,4), (6,3) and (6,6).

No. of favorable outcomes = 12

Probability = 12/36 = 1/3