If AB and CD are the two diameters of a circle with centre at O and if ZOBD = 50°, find ZAOC.
O 120°
0459
0 60°
80°
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Given: ∠OBD = 50°
Here, AB and CD are the diameters of the circles with centre O.
∠DBC = 90° ….(i) [Angle in the semi-circle]
Also, ∠DBC = 50° + ∠OBC
90° = 50° + ∠OBC
or ∠OBC = 40°
Again, By degree measure theorem: ∠AOC = 2 ∠ABC
∠AOC = 2∠OBC = 2 x 40° = 80°
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