Question

If ab + b + a = 135 bc + b + c = 322 ca + a + c = 151 what is the value of a + b + c? 40

Answer 1

Answer:

Step-by-step explanation:

a+b+ab=135. a=(135-b)/(1+b)_______(1)

a+c+ac=151. c=(151-a)/(1+a)__________(2)

c=(151-((135-b)/(1+b)))/(1+((135-b)/(1+b)))

=(151+151b-135+b)/(1+b+135-b)

=(152b+16)/136

=(76b+8)/68

c=(19b+2)/17

b+c+bc=322.

c=(322-b)/(1+b)

(19b+2)/17=(322-b)/(1+b)

(19b+2)(1+b)=17(322-b)

19b^2+4b-5472=0

By solving this equation we get b=-18 or 16

b=-18 substitute in equation (1)&(2) then get a=-9 &c=-20

Then a+b+c=-9-18-20=-47

If b=16 substitute this in equation (1)&(2) then get a=7&c=18

Then a+b+c=7+16+18=41