Question

if ab =bc=ab,then b+c always equals
(a).1/bc
(b).1/2bc
(c).1
(d).bc

Answer 1

Thank you for asking this question, here is your answer:

a^b= b^c = ab

a^b = ab

Now we will take the log on both sides.

log a^b = logab

we know that log AB = log A + log B

logA^B = BlogA

bloga = loga+logb

bloga - loga = logb

(b-1) loga = logb

log^(b-1) = logb

Now we will remove the log from both sides.

a^(b-1) = b

now we will put the value of b

(a^(b-1))^c = aa^(b-1)

a^cb-c = a^(b-1)+1

bc - c = bbc−c=b  

b + c = bc  

hence, b + c = bc

If there is any confusion please leave a comment below.