Question

If AB,BC and CD are equal chords of a circle with Centre O and AD diameter then angle AOB is equals to

Answer 1

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Answer 2

Angle AOB=60 degrees

Step-by-step explanation:

AB, BC and CD are chords of circle with center O.

AB=BC=CD

AD is a diameter of circle.

We know that

Angle subtended at center  by equal chords are equal.

Therefore, by this property

Angle AOB=Angle BOC=Angle COD

Angle AOB+angle BOC+angle COD=Angle AOD=180 degrees

Reason:Straight angle =180 degrees

Angle AOB+angle AOB+angle AOB=180

$3\angle AOB=180$

$\angle AOB=\frac{180}{3}=60^{\circ}$

Hence, angle AOB=60 degrees

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