Question

if ab+bc+ca=10, a^2+b^2+c^2=44 find a^3+b^3+c^3-3abc


pls give the solution​

Answer 1

Answer:

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Answer 2

Answer:

Using the given values

${(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca)$

${(a + b + c)}^{2} = 44 + 2(10)$

${(a + b + c)}^{2} = 64$

$(a + b + c) = 8$

Then

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - (ab + bc + ca))$

Substitute

= 8 × [44-10]

= 8 × 34

= 272