Question

if ab+bc+ca= 36 and a sq+b sq+c sq=85 find a+b+c​

Answer 1

Answer:

a + b + c = 11

Step-by-step explanation:

${(a + b + c)}^{2} = {a}^{2} + {b}^{2} + {c}^{2} + 2(ab + bc + ca) \\ = > {(a + b + c)}^{2} = 85 + 36 \\ = > {(a + b + c)}^{2} = 121 \\ = > a + b + c \: = \sqrt{121} \\ = > a + b + c \: = 11$

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Answer 2

Step-by-step explanation:

may be it will help you !!!