Question

if AB = C where A is a matrix of order 2× 4 and C is a matrix of order 2 × 5 then what is the order of B​

Answer 1

Step-by-step explanation:

two matrices A and B are said to be conformable for the product AB if the number of the columns in A is equal to number of the rows in B

here with the help of this definition you can find the answer

Answer 2

Order of matrix B=$4\times 5$

Step-by-step explanation:

Given :

AB=C

Let order of matrix B=$4\times m$

Because when two matrix are multiplied then number of columns of firts matrix=Number of rows of second matrix

Order of matrix A=$2\times 2$

Number of rows in matrix,n=2

Number of columns in matrix A,m=2

Order of matrix C=$2\times 5$

Number of rows in matrix C=2

Number of columns in matrix C=5

When order of matrix A=$n\times 2$

Order of matrix B=$2\times m$

Order of matrix =AB=C=$n\times m$

Therefore, order of matrix C=$2\times 5$

By comparing we get m=5

Order of matrix B=$4\times 5$

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