If AB||CD , and x:y = 3:7 . Find x. ?
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In the given figure,AB∥CD,CD\parallel EFandy:z=3:7
Let y=3a and z=7a
∠DHI=y(vertically opposite angles)
∠DHI+∠FIH=180
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(Interior angles on the same side of the transversal)
⇒y+z=180
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⇒3a+7a=180
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⇒10a=180
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or a=18
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∴y=3×18
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=54
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and z=7×18
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=126
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Also,x+y=180
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⇒x+54
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=180
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∴x=180
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−54
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=126
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Hence,x=126
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