if AB || CD, then the measure
of angle ACD is
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Answered by
1
Answer:
As AB || DE, AE is crossing both the parallel lines.
So, ∠BAE=∠AED=40
o
In △CDE
∠AED+∠EDC+∠DCE=180
43+40+∠DCE=180
∠DCE=97
As ace is straight line
So, ∠DCE+∠ACD=180
∠ACD=180−97=83
Answer 83..
Answered by
0
Answer:
The answer is 88
Thank you
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