if AB||DE, find angle ACD
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given: AB|| DE
find : angle ACD
proof: angle A= angle E (AB || DE)
angle E = 35
in triangle DEC
angle D + angle E + angleDEC =180 (angle sum property)
53 +35 + angle DCE =180
88 + angle DCE =180
angle DCE = 180-88
angle DCE = 92
angle ACD + DCE =180 (linear pair )
angle ACD + 92 =180
ACD = 180-92
ACD = 88
it may help you
find : angle ACD
proof: angle A= angle E (AB || DE)
angle E = 35
in triangle DEC
angle D + angle E + angleDEC =180 (angle sum property)
53 +35 + angle DCE =180
88 + angle DCE =180
angle DCE = 180-88
angle DCE = 92
angle ACD + DCE =180 (linear pair )
angle ACD + 92 =180
ACD = 180-92
ACD = 88
it may help you
ckaushik:
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