Question

if ab is a chord of a circle with centre p and radius 20cm if ab is equall 32cm then find the distance of the chord ab from the centre p​

Answer 1

Let's consider ΔOAD as RHS triangle,

• OD (Distance between the Centre and radius of the circle) = ?

• OA (Radius of the circle) = 16 cm

• AD (1/2 of the chord AB) = 1/2×32 cm = 16 cm

As per Pythagoras theorem,

⇒ OD² + AD² = OA²

⇒ OD² + (16 cm)² = (20 cm)²

⇒ OD² + 256 cm² = 400 cm²

⇒ OD² = 400 cm² - 256 cm²

⇒ OD = √144 cm²  [The value of √144 cm² is 12cm]

⇒ OD = 12 cm

∴ The distance between the chord and the Centre of the circle is 12 cm.

{see the attachment for more information and it will definitely help you}

Hope this helps you.

Thankyou for your question.

Mark me as Brainleist.