if AB parallel to CD parallel to EF . find the value of x
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Answer:
x=20°
Step-by-step explanation:
It is given that AB∥CD and BC is transversal
from the figure we know that ∠BCD and ∠ABC are alternate interior angles
so we get
- ∠ABC=∠BCD
in order to find the value of x we can write it as
- x+∠ECD=70° ....(i)
It is given that CD∥EF and CE is transversal
from the figure we know that ∠ECD and ∠CEF are consecutive interior angles
so we get
- ∠ECD+∠CEF=180°
by substituting the values
- ∠ECD+130° =180°
- ∠ECD=180°−130°
- ∠ECD=50°
Now by substituting ∠ECD in equation (i) we get
- x+∠ECD=70°
- x+50° =70°
- x=20°
- therefore the value of x is 20°
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