if AB parallel to EF , DE parallel to BC AC parallel to DF find x and y
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Let, Point P be the intersection of AB and DE.
=> ∠APD = 110 degrees Vertically Opposite angles
=> ∠DMB = ∠AME = 70 Degrees
Let, Q be the intersection of AB and DF
In Triangle DPQ,
∠DQP = 180 Degrees - 60 Degrees - 70 Degrees
∠DQP = 50 degrees
=> DFE = 50 Degrees (Interior angles as AB parallel to EF
Similarly you can compute remaining angles.
You will get
x = 120 degrees and y = 120 degrees
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