Question

speed distance and time chapter class 5 any one send me

Answer 1

Ok
The whole chapter do u need and from which book

Answer 2

SSCSSC CGLQuantitative AptitudeArticle

Important Concepts & Short Tricks on Speed, Distance & Time454 upvotes121 comments

Dear Readers,

We are providing you Important Short Tricks on Speed, Distance & Time which are usually asked in SSC Exams. Use these below given short cuts to solve questions within minimum time. These shortcuts will be very helpful for your upcoming SSC CHSL Exam 2015.

Important formulae and facts of Time and Distance

Speed is a very basic concept in motion which is all about how fast or slow any object moves. We define speed as distance divided by time.
Distance is directly proportional to Velocity when time is constant.

Speed Distance Time formula mathematically written as:- Speed= distance/time

Formula of Time :-time = distance/ Speed
So Formula of time is, time is equal to distance upon speed.

Formula of Distance:-Distance = (Speed * Time)

Distance = Rate x Time

To find rate, divide through on both sides by time:

Rate = Distance/Time

Rate is distance (given in units such as miles, feet, kilometers, meters, etc.) divided by time (hours, minutes, seconds, etc.). Rate can always be written as a fraction that has distance units in the numerator and time units in the denominator, e.g., 25 miles/1 hour.

So distance is simply speed into time.
Note: All three formulae that formula of speed, formula of time and formula of distance are interrelated.

Convert from kph (km/h) to mps(m/sec)
For converting kph(kilometre per hour) to mps(meter per second) we use following formula

x km/hr=(x∗5/18) m/sec

Convert from mps(m/sec) to kph(km/h)
For converting mps(meter per second) to kph(kilometre per hour) we use following formula

x m/sec= X *(18/5)  km/h

If the ratio of the speeds of A and B is a : b, then the ratio of the times taken by then to cover the same distance is :1/a : 1/b  or  b : a Suppose a man covers a certain distance at x km/hr and an equal distance at y km/hr. Then,
the average speed during the whole journey is :- 2xy/(x + y) Relation between time, distance and speed: Speed is distance covered by a moving object in unit time: Speed= Distance covered/ Time Taken

Rule : 1: Ratio of the varying components when other is constant: Consider 2 objects A and B having speed  Sa, Sb.
Let the distance travelled by them are Da and Db respectively and time taken to cover these distances be Ta and Tb respectively.
Let's see the relation between time, distance and speed when one of them is kept constant

When speed is constant distance covered by the object is directly proportional to the time taken.
ie; If Sa=Sb then   Da/Db = Ta/TbWhen time is constant speed is directly proportional to the distance travelled. ie; If Ta=Tb then Sa/Sb=Da/DbWhen distance is constant speed is inversely proportional to the time taken ie if speed increases then time taken to cover the distance decreases. ie; IfDa=Db then  Sa/Sb= Tb/Ta

Rule 2: We know that when distance travelled is constant, speed of the object is inversely proportional to time taken

If the speeds given are in Harmonic progression or HP then the corresponding time taken will be in Arithmetic progression or APIf the speeds given are in AP then the corresponding time taken is in HP

Distance Constant

If distance travelled for each part of the journey, ie d1=d2=d3=...=dn=d, then average speed of the object is Harmonic Mean of speeds.
Let each distance be covered with speeds s1,s2,...sn in t1,t2,...tn times respectively.
Then t1 =d/s1
t2 = d/s2
tn =d/sn

then, Average Speed=   [(d + d + d+ ... ntimes)]/ [d/s1 + d/s2+ d/s3+ ... d/sn

Average Speed= (n)/[(1/s1  + 1/s2+ .... 1/sn)]

Time Constant

If time taken to travel each part of the journey, ie t1=t2=t3=…tn=t, then average speed of the object is Arithmetic

Let distance of parts of the journey be d1,d2,d3,...dn and let them be covered with speed s1,s2,s3,...sn respectively.
Then d1=s1 t ,  d2=s2t, d3=s3t, ... dn=snt
then ,  Average Speed= [(s1/t+ s2/t+ .... sn/t)/(t + t+ ...  ntimes)]

Average Speed=( s1+ s2+s3+ ... + sn)/n

Relative Speed

If two objects are moving in same direction with speeds a and b then their relative speed is |a-b|If two objects are moving is opposite direction with speeds aand b then their relative speed is(a+b)