if abc=1, then (1+a+b^-1)^-1
PLEASE solve this fully here
Answers
Answered by
0
(1+a+1/b)^-1
(b/b+ab/b+1/b)^-1
b/b+ab+1
(b/b+ab/b+1/b)^-1
b/b+ab+1
Similar questions