if abc are in ap a+k b+k c+k are also in ap
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Since a, b, and c are in AP
2b = a + c .....(i)
Now, on adding k to the numbers a, b, and c :-
The new no.s are = (a + k), (b + k), and (c + k)
For them to be in AP :-
(c + k) - (b + k) = (b + k) - (a + k)
c + k - b - k = b + k - a - k
c - b = b - a
a + c = 2b
{which is true from the equation (i)}
Hence, the no.s (a+k), (b+k), (c+k) are also in AP
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