Question

if ∆ABC~∆DEF and their sides of lengths are marked along them,then find the lengths of sides of each ∆​

Answer 1

Step-by-step explanation:

as triangles are similar

then

$\frac{ab}{bc} = \frac{bc}{ef} = \frac{ac}{df} \\ \frac{2x - 1}{18} = \frac{2x + 2}{3x + 9} = \frac{3x}{6x } \\ \frac{2x - 1}{18} = \frac{3x}{6x} \\ \frac{2x - 1}{18} = \frac{1}{2} \\ 4x - 2 = 18 \\ 4x = 20 \\ x = 5$

ab=2x-1=2×5-1=9

ac=3x=3×5=15

bc=2x+2=2×5+2=12

ef=3x+9=3×5+9=15+9=24

df=6x=6×5=30

Answer 2

Answer:

30

Step-by-step explanation:

I will be clip the answer in the up