If ∆ABC ~ ∆DEF, BC = 3EF and ar (∆ABC) = 117cm² find area (∆DEF).
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Two Triangles are said to be similar if their i)corresponding angles are equal and ii)corresponding sides are proportional.(the ratio between the lengths of corresponding sides are equal)
•Similarity of triangles should be expressed symbolically using correct correspondence of their vertices
SOLUTION:
GIVEN:
∆ABC ~ ∆DEF
ar(∆ABC) = 117 cm²
BC = 3EF
ar( ∆ABC) / ar( ∆DEF ) = (BC / EF)²
[The ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides]
117 / ar( ∆DEF ) = (3EF /EF)²
117 / ar( ∆DEF ) = (3 /1)²
117 / ar( ∆DEF ) = 9/1
9 × ar( ∆DEF ) = 117
ar( ∆DEF ) = 117/9
ar( ∆DEF ) = 13 cm²
Hence, the ar( ∆DEF ) = 13 cm²
HOPE THIS WILL HELP YOU....
•Similarity of triangles should be expressed symbolically using correct correspondence of their vertices
SOLUTION:
GIVEN:
∆ABC ~ ∆DEF
ar(∆ABC) = 117 cm²
BC = 3EF
ar( ∆ABC) / ar( ∆DEF ) = (BC / EF)²
[The ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides]
117 / ar( ∆DEF ) = (3EF /EF)²
117 / ar( ∆DEF ) = (3 /1)²
117 / ar( ∆DEF ) = 9/1
9 × ar( ∆DEF ) = 117
ar( ∆DEF ) = 117/9
ar( ∆DEF ) = 13 cm²
Hence, the ar( ∆DEF ) = 13 cm²
HOPE THIS WILL HELP YOU....
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