Question

if ΔABC ~ ΔDEF ,BC = 4 cm, EF = 5 cm and ar (Δ ABC ) = 80 cm square, the ar (ΔDEF) is:

Answer 1

Area of traingle ABC = 1/2 × base ×height1
80 sq. cm = 1/2 × 4 × height
height = 80 × 2/4
height = 40cm
ABC ~ DEF
BC/EF = height1/height2
4/5 = 40/height2
height2 = 40 × 5/4
height2 = 50cm

Now, Area of triangle DEF = 1/2 × base × height2
=1/2 × 5 × 50
=125 sq. cm
Ans: Area of Triangle DEF is 125 sq. cm


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Answer 2

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