If ABC is a isosceles right angle triangle
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Step-by-step explanation:
B is a right angle so sin B = 1.
Since it is an isosceles triangle, A = C = 45°, so sin A = cos C = 1 / √2
sin² A + cos² C - sin² B
= 1/2 + 1/2 - 1
= 0
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In isosceles right angle triangle
angle_B=90°
angle A=45°
angle C=45°
from triangle ABC,
SinA=1÷1.414
SinB=1
CosC=1÷1.414
sinA×SinA+CosB×CosB-sinB×sinB
1÷2+1÷2-1
1-1
0
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