Math, asked by vamshikrishna777, 10 months ago

If ABC is a isosceles right angle triangle​

Attachments:

Answers

Answered by Anonymous
2

Answer:

0

Step-by-step explanation:

B is a right angle so sin B = 1.

Since it is an isosceles triangle, A = C = 45°, so sin A = cos C = 1 / √2

sin² A + cos² C - sin² B

= 1/2 + 1/2 - 1

= 0


Anonymous: Hope this helps. Plzzz mark it Brainliest. All the best!!!
vamshikrishna777: kk
Answered by sejupashte30
0

In isosceles right angle triangle

angle_B=90°

angle A=45°

angle C=45°

from triangle ABC,

SinA=1÷1.414

SinB=1

CosC=1÷1.414

sinA×SinA+CosB×CosB-sinB×sinB

1÷2+1÷2-1

1-1

0

Similar questions