Question

If ABC is a right angle isosceles triangle, then find its greatest angle?ਜੇਕਰ ABC ਸਮਕੋਣੀ ਸਮਦੋਭੁਜੀ ਤ੍ਰਿਭੁਜ ਹੈ ਤਾਂ ਇਸਦਾ ਸਭ ਤੋਂ ਵੱਡਾ ਕੋਣ ਪਤਾ ਕਰੋ Iयदि ABC समकोण समद्विबाहु त्रिभुज है, तो उसका सबसे बड़ा कोण ज्ञात कीजिए? *

90°

180°

120°

60°

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Answer 1

Answer:

180 degree is your correct answer

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Answer 2

Given:-

• If ABC is a right angled Isosceles triangle.

• $\sf{\angle{B} = 90^{\circ}}$

To Find:-

• The Greatest angle

Concept used:-

• In an Isosceles triangle two sides are equal.

• angles opposite to equal sides are equal.

Now,

Let the equal sides be "x"

→ AC = BC

→ $\sf{\angle{A} = \angle{C}}$ ( using concept)

→ $\sf{\angle{A} + \angle{B} + \angle{C} = 180^{\circ}}$

→ $\sf{ x + 90 + x = 180}$

→ $\sf{ 2x + 90 = 180}$

→ $\sf{ 2x = 90}$

→ $\sf{ x = \dfrac{90}{2}}$

→ $\sf{ x = 45^{\circ}}$

Hence, The Value of x is 45°

Therefore, The angles of this triangle are 90°, 45° & 45°

So, The Greatest angle is 90°