Question

If ABC is a right angled triangle at B and M, N are
the mid-points of AB and BC, then 4 (AN² + CM²)
is equal to
(1) 4AC²
(2) 6AC²
(3) 5AC²
(4) 5/4AC²​

Answer 1

Answer:2. 6(ac)2

Step-by-step explanation:

Use mid point Therom with mn = half of ac

AN square= AB square + BN square

CM square = BM square + BC square

AN square + CM square = AN s. + BN s. + BM s. +BCs.

= AC square + MN square

Half of AC square+ AC square

3/2 AC square

4(3/2 AC square)

6AC square