Math, asked by dreamsmpgamer28, 1 day ago

if abc is a triangle and parallel bc and p and q are the two points on the side ab and ac.then find the value of aq:qc given ap:ab=3:5​

Answers

Answered by gudluuu7rk
0

Hint- Proceed the solution of this question, first with the help of basic proportionality theorem find the unknown side that we can easily so that we can prove two corresponding triangles similar. Hence once we show a triangle similar then easily with the help of properties of a similar triangle we can find the desired sides of the triangle.

Complete step-by-step solution -

In the question it is given that Δ ABC, AP = 2.4 cm, AQ = 2 cm, QC = 3 cm, and BC = 6 cm. Also, PQ ∥ BC. And we were required to find: AB and PQ.

By using Thales Theorem, which is a Basic proportionality theorem,

we have Asit′sgiventhatPQ∥BC

⇒APPB=AQQC

⇒2.4PB=23

On cross multiplication

⇒PB=2.4×32=3.6 cm

Now finding, AB = AP + PB

AB = 2.4 + 3.6 ⇒ AB = 6 cm

Now, considering Δ APQ and Δ ABC

We have,

⇒∠A = ∠A (common)

⇒ ∠APQ = ∠ABC (Corresponding angles are equal, PQ||BC and AB being a transversal)

We know that the mathematical definition for similar triangles states that the triangles (Δ APQ and Δ ABC) have proportional corresponding sides and all the corresponding angles are the same. The Angle-Angle (AA) criterion tells us that two triangles are similar if two corresponding angles are equal to each other.

Thus, Δ APQ and Δ ABC are similar to each other by AA criteria.

Now, we know that Corresponding parts of similar triangles are proportional.

⇒APAB=PQBC

On cross multiplication

⇒PQ=AP×BCAB

⇒PQ=2.4×66

∴PQ = 2.4 cm

Note- In this particular system we should know that Thales theorem states that

If two lines AB and CD as shown in below figure. When AC and BD intersect at a point E, and when E is either (1) a point interior to both segment AC and segment BD or else (2) exterior to both segments, then the triangles AEB and CED (1) share the angle ∠AEB = angle ∠CED or else (2) these two angles are vertical angles. Then for such a figure as shown below

Line AB is parallel to line CD if and only if

Triangle AEB is similar to triangle CED if and only if

ECEA=EDEB

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