Question

If ABC is a triangle in which A (0,2) B (4,0) . If (4,4) is the mid point of BC then find mid point of AC

Answer 1

Step-by-step explanation:

midpoint M is ( (-1+6)/2 , (-2+2)/2 ) = ( 5/2 , 0)

midpoint N is ( (-1+4)/2 , (-2+6)/2 ) = ( 3/2 , 2)

slope BC = (6-2)/(4-6) = 4/-2 = -2

slope of MN - (0-2)/(5/2 - 3/2) = -2

So BC is || to MN

length of BC = √( (6-2)^2 + (4-6)^2) = √(16+4)

= √20 = 2√5

length of MN = √( (0-2)^2 + (5/2-3/2)^2

= √( 4+1) = √5

which is 1/2 of BC