if ️ABC is an isosceles triangle such that AB=AC, then prove that altitude AD from A on BC bisects BC.
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There are two right triangles ADB and ADC we have
Hyp. AB = Hyp. AC (Given)
AD = AD (Comman side)
So by RHS criterion of congruence
△ADB≅△ADC
BD = DC ( ∵ Corresponding parts of congruent triangles are equal )
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