Question

if ABC is an isosceles triangle such that AB = BC then prove that altitude AD from A on BC bisects BC.

Answer 1

Hi Friends ✋✋



Given :-

AB = AC

Therefore < ABD = < ACD

AD is a altitude

then < ADC = < ADB = 90°

To Prove :-

BD = CD

Proof :-

In ∆ ADB and ∆ ADC

AB = AC ...........( Common )

< ADB = < ADC = 90°

AB = AC ..........( Given )

Therefore by RHS Congruency Rule



∆ ADB ≈ ∆ ADC

Therefore,

BD = CD ..............(C.P.C.T)

therefore AD bisects BC .


Hope it helps

Answer 2

Answer:

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