If ∆ABC is congruent to ∆DEF ,angle a =30°,angle b= 50°,angle f=?
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Answered by
8
If Angle A = 30° and Angle B = 50°
Therefore,
In ABC, we get;
Angle (A + B + C) = 180°
=> 30° + 50° + ANGLE C = 180
=> Angle C = 100°
Now,
ABC and DEF are congruent to each other
Since, Angle F = Angle C = 100°
Therefore,
In ABC, we get;
Angle (A + B + C) = 180°
=> 30° + 50° + ANGLE C = 180
=> Angle C = 100°
Now,
ABC and DEF are congruent to each other
Since, Angle F = Angle C = 100°
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