Question

if abc is similar to def and their areas are 81 cm2 and 169 cm2 resp. And ac=7.2cm .find df

Answer 1

Answer:

by theorem area of similar triangles

arABC/arDEF = (AC/DF)^2

81/169 = (7.2/DF)^2

√81/169 = 7.2/DF

9/13 = 7.2/DF

DF= 7.2×13/9

= 10.4cm