If ∆ABC~∆PQR, area (∆ABC)= 80cm^2 and area (∆PQR)= 245cm^2 AB/PQ is equal to:
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Answer:
ΔABC ∼ΔPQR.
Area of ΔABC/Area of ΔPQR = (AB/PQ)^2
80/245 = (AB/PQ)^2
4root5/7root5 = AB/PQ
∴ AB/PQ = 4root5/7root5
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