If ∆ ABC~∆PQR.The area of a triangle ABC is 121 square cm, the area of PQR is 81 sqare cm and BC= 4 cm find the leanth of QR
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area of triangle ABC/ Area of triangle PQR
= BC/QR
(121)2/(81)2 = 4/QR
11/9=4/QR
11×QR=4×9
QR = 36/11
= BC/QR
(121)2/(81)2 = 4/QR
11/9=4/QR
11×QR=4×9
QR = 36/11
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