Question

If ∆ABC =~ ∆PQR, then find the values of X and y.
please friends tell it solution l know it's answer please tell solution​

Answer 1

If ∆ABC is congruent to ∆PQR

:–angleA = angleP

=> 105° = (2y - 5)°

=> (2y - 5)° = 105°

=> 2y = 105° + 5°

=> 2y = 110°

=> y = 110°/2

=> y = 55°

:–angleC = angleR

=> 40° = (2x + 8 )°

=> (2x + 8)° = 40°

=> 2x = 40° - 8

=> 2x = 32°

=> x = 32°/2

=> x = 16°

I hope this answer helps you.

Answer 2

Solution :

$\checkmark \sf (2x +8) \degree = 40 \degree \underline{ \: \: \: \: \: \: \: \: }(1) \\ \\ \checkmark \: \sf(2y - 5) \degree = 105 \degree \underline{ \: \: \: \: \: \: \:}(2) \\ \\ \bf [\because \triangle ABC \cong \triangle PQR ]$

solving these equations

$\begin{array}{c |c} \sf2x + 8 = 40& \sf2y - 5 =105 \\ \\ \therefore \: {\color{green} \tt \: x = 16}& \therefore \color{green} \tt \: y = 55\end{array} \\ \\ \\ \\ \\ \small \tt\colorbox{aqua}{@StayHigh}$