If ΔABC ~ ΔQRP (ar(ΔABC))/(ar(ΔPQR))=9/4,AB=18cm and BC=15cm, then find the length of PR.
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Answered by
4
Given :
Area of ∆ ABCArea of ∆QRP = 94
AB = 18 cm , BC = 15 cm So PR = ?
We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.
Area of ∆ ABCArea of ∆ QRP = AB2QR2 = BC2PR2 = AC2QP2
So , we take
Area of ∆ ABCArea of ∆ QRP = BC2PR2
Now substitute all given values and get
94 = 152PR2
Taking square root on both hand side , we get
32 = 15PR
PR = 10 cm
Area of ∆ ABCArea of ∆QRP = 94
AB = 18 cm , BC = 15 cm So PR = ?
We know when two triangles are similar then " The areas of two similar triangles are proportional to the squares of their corresponding sides.
Area of ∆ ABCArea of ∆ QRP = AB2QR2 = BC2PR2 = AC2QP2
So , we take
Area of ∆ ABCArea of ∆ QRP = BC2PR2
Now substitute all given values and get
94 = 152PR2
Taking square root on both hand side , we get
32 = 15PR
PR = 10 cm
Answered by
34
Solution:
Given:
- ΔABC ~ ΔQRP.
- ar (ΔABC) / ar (ΔQRP) =9/4
- AB = 18 cm and BC = 15 cm
We know that the ratio of the areas of two similar triangles is equal to the square of the ratio of their corresponding sides.
➨ar (ΔABC) / ar (ΔQRP) = BC²/RP²
➨9/4 = (15)²/RP²
➨RP2 = (4/9) ×225
➨PR2 = 100
Therefore,
PR = 10 cm
Hope it will be helpful :)
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