Math, asked by syedafroz8892, 1 month ago

if ABCD as a parallelogram find the value of x and y were AB is 2x+3y , BC is 8, CD is 22 , DA is x+y ?​

Answers

Answered by kishandevganiya8
0

Step-by-step explanation:

Since ABCD is a parallelogram, AB∥DC and AD∥BC

Now, AB∥DC and transversal BD intersects them.

∴∠ABD=∠BDC since alternate angles are equal.

⇒10x=60

⇒x=

10

60

=6

And, AD∥BC and transversal BD intersects them.

∴∠DBC=∠ADB

⇒4y=28

⇒y=

4

28

=7

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