If ABCD is a parellogram , then show that the bisectors of any two adjacent angles of the parellogram are at right angles.
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let ABCD BE THE llgm
we know that
ANGLE A + ANGLE B = 180 DEGREE
THEREFORE
1/2 A + 1/2 B = 90 DEGREE -(1)
AND WE KNOW THAT
IN TRIANGLE AOB
ANGLE BAO + ANGLE ABO + ANGLE AOB = 180 (ANGLE SUM PROPERTY)
=> 1/2 A + 1/2 B + AOB = 180
=> AOB = 180 -( 1/2 A + 1/2 B)
=> AOB = 180 - 90 (FROM 1)
=> AOB = 90 => ANGLE BISECTOR OF 2 ADJ. ANGLES INTERSECT AT 90
HENCE PROOVED
Hope This helps :)
Rriya2510:
hi
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